topic Re: How to get the coordinates of a line in gdl? in GDL

How to get the coordinates of a line in gdl?

LeeJaeYoung — Tue, 04 Oct 2022 14:42:00 GMT

In gdl, we know the coordinates of p1 and p2 and we know the distance from x1 to x4. Then how do we get the coordinates of x1~x4?

2D
We know the coordinates of p1 and p2. And we know the distance from p1 to x4.
1. How do you find the angle with p1 and p2?
2. How do you find the coordinates of x4? (Example: Autolisp (setq x4 (polart p1 angle distance))
3. How do you find the coordinates of x3?

Do I need to convert to radians when using angles?

Thanks for reading.

Re: How to get the coordinates of a line in gdl?

Miha Nahtigal — Tue, 04 Oct 2022 15:35:25 GMT

1. calculate the angle of the line to y or x axis

2. rot2 command - rotate the coordinate system so the line between p1 and p2 is vertical or horizontal

3. the rest should be easy... you have only straight lines to draw between points

Re: How to get the coordinates of a line in gdl?

LeeJaeYoung — Tue, 04 Oct 2022 16:09:35 GMT

It means using ADD2 and ROT2 to handle it.
thank you ^^

Re: How to get the coordinates of a line in gdl?

julienK — Wed, 05 Oct 2022 12:42:51 GMT

the easiest way to find the coordinates of a point on a line is to use the parametric equation of a line:

x4 = x1+((x2-x1)*(ratio))
y4 = y1+((y2-y1)*(ratio))

with p1(x1,y1) p2(x2,y2).

ratio is a number between 0 and 1 representing the distance from p1 to p2

just a bit of math to find the rest:

!p1 & p2 xp1 = -5 yp1 = 0 xp2 = 0 yp2 = 5 !distance from p1 to x4 p1 to x1 ratio = .25 x4 = xp1+((xp2-xp1)*(ratio)) y4 = yp1+((yp2-yp1)*(ratio)) x1 = xp1+((xp2-xp1)*(1-ratio)) y1 = yp1+((yp2-yp1)*(1-ratio)) !slope of the line need to find x3 and x2 THETA = atn((yp2-yp1)/(xp2-xp1)) ! distance between x3 and x4 offset = 2 ! coordinates of point x3 x3 = x4+ offset *cos(90+THETA) y3 = y4+ offset *sin(90+THETA) x2 = x1+ offset *cos(90+THETA) y2 = y1+ offset *sin(90+THETA) !draw lines line2 xp1,yp1,xp2,yp2 line2 x4,y4,x3,y3 line2 x1,y1,x2,y2 line2 x3,y3,x2,y2

Re: How to get the coordinates of a line in gdl?

LeeJaeYoung — Wed, 05 Oct 2022 13:16:35 GMT

Could you please explain the formula to find the ratio in an easy way?

Re: How to get the coordinates of a line in gdl?

julienK — Wed, 05 Oct 2022 13:57:48 GMT

The ratio is just a value you chose of how far along the line x4 and x1 are.

if you use .5 it will be in the middle.

Copy the full code I posted in a new object 2D script and change to value of ration and offset to see how the 2D view changes.

Re: How to get the coordinates of a line in gdl?

LeeJaeYoung — Wed, 05 Oct 2022 23:30:40 GMT

!p1 & p2 xp1 = HA yp1 = B-D2-0.05 xp2 = 0 yp2 = B !distance from p1 to x4 p1 to x1 ratio = .1 ratio1 = .11 x4 = xp1+((xp2-xp1)*(ratio1)) y4 = yp1+((yp2-yp1)*(ratio1)) x1 = xp1+((xp2-xp1)*(1-ratio)) y1 = yp1+((yp2-yp1)*(1-ratio)) !slope of the line need to find x3 and x2 THETA = atn((yp2-yp1)/(xp2-xp1)) + 180 ! distance between x3 and x4 offset = 0.05 ! coordinates of point x3 x3 = x4+ offset *cos(90+THETA) y3 = y4+ offset *sin(90+THETA) x2 = x1+ offset *cos(90+THETA) y2 = y1+ offset *sin(90+THETA) !draw lines line2 xp1,yp1,xp2,yp2 line2 x4,y4,x3,y3 line2 x1,y1,x2,y2 line2 x3,y3,x2,y2

Re: How to get the coordinates of a line in gdl?

LeeJaeYoung — Wed, 05 Oct 2022 14:42:34 GMT

thank you so much