I am working with the MASS command and the manual says
the "s" (status of edges) is "similar to the Prism_ statement".
Similar but not identical in my experience.
I have found that if you use the status value of -1 (an illegal value
for the PRISM_ statement) in the parameters for the ridge lines
you can hide the ridge lines.
I would like to hide all of the edges of the mass polygon (the mass perimeter).
I can get all polygon edges to hide except the first one using
the the status value of 8. This value works perfectly to hide
all the edges in the PRISM_ command but does not work for
the MASS command.
I have resorted to extending the edge that won't hide and then
cutting that edge off with a CUTPOLA command (very tacky).
Does anyone know how to hide all the edges of the mass polygon ?
Peter wrote: Does anyone know how to hide all the edges of the mass polygon ?
I also ran up against this a few months ago and came to the conclusion that the visibility of the top surface line of the MASS perimeter is non-negotiable. I've been mirroring MASSes to create symmetrical three dimensional mesh objects, but the zipper line down the middle is a killer.
Your CUTPOLYA solution is at least a workable cheap trick.
Thank you for replying.
The MASS command I am working with has a hole in it made
with the -1 syntax. If I eliminate the hole all edges can be
hidden in the expected way using the status value 8.
In my case I used CUTPOLYA to cut the hole I needed instead
of the -1 method.
I too use the MASS command to make symmetrical objects and
In versions prior to AC 8 one could set up a CUTPOLYA command
exactly at the coordinates of a surface of an object and hide all
edges laying at that surface. But in AC 8 and above one must
extend the the surface some amount and then cut it with
CUTPOLYA to hide the edges. Why GS changed this is a mystery to me.
In the case of my MASS, before I discovered the issue concerning
holes, this method of extending an edge did not work well when
certain angle parameters values approached zero or ninety degrees.
Again, thanks for replying,