A month ago I have send my first e-mail to developer-registration a
request for a pro-forma invoice for Archicad developer license and one
year support. After two weeks of patient waiting for a response and
receiving none, I have chosen a different r...
I have hard time getting a position of a camera with axonometric
projection.The 3x3 Transformation gives just info on direction and
axonomtery in general. Camera->GetViewPoint() works only for
perspective. How can I figure out a center of a view?
Hi,There are few mistakes in the documentation of CHANSI2Unicode. long
CHANSI2Unicode ( const char* pChars, // string to convert long nChars,
// number of bytes in string wchar_t* pWChars, // wide-char buffer long
maxWChars, // wide char buffer lengt...
Hello All,I am considering a development of an integration of a
rendering engine into Archicad 16 , 15. What are recommended IDE for
Windows and Mac?I have read that Xcode 3.2.6 works well and I am not
sure about which version of VC++ will be good. W...
stefan wrote:As an alternative, is there a nice example in the Devkit
which uses an external text file to read and write into? There is
ModelAccess_Test in the 16 FullSDK with ModelAccess_Test_Writer, which
may be helpful.
Thank you. I understand now. The bounding box is positioned in relation
to project origin. This will help me finding the "central" axis. For my
application I have to specify a position in 3D to avoid clipping so
typical in parallel projection. I will...
ivanfi wrote:Calling GetBounds () on the axonometric camera tells you
the bounding box of the region that should be displayed. The center of
the view is the center of this bounding box. Bounding box gives me just
horizontal and vertical size of a vis...
The ExampleRenderingAddOn supplied with SDK 16 renders the view
correctly, so there must be a way of figuring out a center of the view.
I am surprised GS didn't supply such a basic functionality in their SDK.
I have spent few hours analyzing the exam...