How can I determine the corner coordinate of a door opening?

[Anonymous]

Hello Archicad community,

I know the front center point coordinate of my door element (see attachment), and starting from there using the width of the door opening I could calculate the door opening coordinate on the side (see attachment). The problem with fetching the width of the door, however, is that it depends on a setting, so that the door width could include the frame or not (80cm or 100cm). Is there an easy way to always get the full opening width (100cm)? Because if I would simply add the frame widths on both sides (20cm total) I would get 120cm in case the setting already includes the frame widths. If I could directly get the coordinate of the corner via the wall without having to know the door opening width this would also be fine.

Thanks a lot,
Dan

Archicad version: 22

[Tibor Lorantfy · Accepted solution]

Hi Dan,

Using ACAPI_Element_GetQuantities function you can get easily the width and nominal width of the door. The width should be the full width what you are looking for:

API_ElementQuantity quantity;
API_QuantitiesMask  mask;
API_Quantities      quantities;
BNZeroMemory (&quantity, sizeof (API_ElementQuantity));
quantities.elements = &quantity;

ACAPI_ELEMENT_QUANTITY_MASK_CLEAR (mask);
ACAPI_ELEMENT_QUANTITY_MASK_SET (mask, door, width1);
ACAPI_ELEMENT_QUANTITY_MASK_SET (mask, door, width2);
ACAPI_ELEMENT_QUANTITY_MASK_SET (mask, door, nWidth1);
ACAPI_ELEMENT_QUANTITY_MASK_SET (mask, door, nWidth2);
GSErrCode err = ACAPI_Element_GetQuantities (doorGuid, nullptr, &quantities, &mask);
if (err == NoError) {
    ACAPI_WriteReport ("Door quantities:\n
                        Reveal Side Width = %.6lf\n
                        Opposite Side Width = %.6lf\n
                        Reveal Side Nominal Width = %.6lf\n
                        Opposite Side Nominal Width = %.6lf\n",
                        true,
                        quantity.door.width1,
                        quantity.door.width2,
                        quantity.door.nWidth1,
                        quantity.door.nWidth2);
}

Regards,
Tibor

[Anonymous]

Thanks a lot! width1 seems to work as intended.