Morph: Booleon Subtraction, or Slice along a curve
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2021-01-19
03:15 AM
- last edited on
2023-05-24
07:20 PM
by
Rubia Torres
2021-01-19
03:15 AM
Though can not get the internals side to Boolean Subtract, to the shape wanted.
I have over sized the operating shape and it's not cutting the form.
And Slice does not happen work against curve?
Please refer image.
Thank you!
6 REPLIES 6

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2021-01-19 05:47 AM
2021-01-19
05:47 AM
What is subtracting from what? Do you have a reference image of the leg in question you are trying to model?
Ling.
Ling.
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2021-01-19 06:17 AM
2021-01-19
06:17 AM
No, just forming a simple leg.
Please refer image .
Thank you!
Please refer image .
Thank you!

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2021-01-19 07:25 AM
2021-01-19
07:25 AM
By the wireframe, it looks to be already cut? Or are you trying to remove the piece that wraps the corner?
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2021-01-19 07:40 AM
2021-01-19
07:40 AM
Yes, at first it appears that way...
But when a red-line intersection shows up, it indicates a failed Boolean Subtraction.
This is why I over size the Operation object, with most programs this solves any problem.
Cheers!
But when a red-line intersection shows up, it indicates a failed Boolean Subtraction.
This is why I over size the Operation object, with most programs this solves any problem.
Cheers!

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2021-01-19 01:49 PM
2021-01-19
01:49 PM
Not sure what you are trying to achieve, and not sure why it fails like that. Is the table foot you want something like this:
If so, you can see that I could make a SEO / boolean subraction from a morph like this (wireframed ones are the operator elements, made as complex profiles.) You are first subtracting with operator and then you just hide the operator layer, don't you?
But then again, you don't necessarily need boolean for that kind of leg.
I managed to do that with one complex profile, please see attached:
Or maybe I misunderstood and your leg is something totally different..
If so, you can see that I could make a SEO / boolean subraction from a morph like this (wireframed ones are the operator elements, made as complex profiles.) You are first subtracting with operator and then you just hide the operator layer, don't you?
But then again, you don't necessarily need boolean for that kind of leg.
I managed to do that with one complex profile, please see attached:
Or maybe I misunderstood and your leg is something totally different..
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2021-01-23 03:30 AM
2021-01-23
03:30 AM
Your extremely close.. my leg has a splay to it.
I finally got it, but not by Boolean Subtraction. It is not prefect, but enough for the 3D, and can be corrected in any detail.
I understand what you are saying about SEO, you can do that easily. But if you move the hidden component, with out unhiding the hidden operator. The shape is detached, and shape dead.
I think the overall issue is ArchiCAD's dislike of compound shapes. And having the splay to leg, archiCAD hits its limit. I hope a programmer is listening?!
THANK YOU!!
I finally got it, but not by Boolean Subtraction. It is not prefect, but enough for the 3D, and can be corrected in any detail.
I understand what you are saying about SEO, you can do that easily. But if you move the hidden component, with out unhiding the hidden operator. The shape is detached, and shape dead.
I think the overall issue is ArchiCAD's dislike of compound shapes. And having the splay to leg, archiCAD hits its limit. I hope a programmer is listening?!
THANK YOU!!