Some help with trigo

[Anonymous]

I would apreciate some help for this trigonometrical problem.
I am searching for H or ang, function of X and ray. I don't find a solution.
Thanks to anyone for the highligth.

[TomWaltz]

What values do you have? Only X? Or do you have "ray" also? From the diagram,

H = X, 

then

angle = ATN(H/(x+ray)

[James Murray]

H <> X though. H is equal to the other side of that 45º triangle, less than X.

I don't think it's solvable with the information given. You have one side and no angles, which isn't much.

Hoping I'm wrong,

[Anonymous]

TomWaltz wrote:
What values do you have? Only X? Or do you have "ray" also? From the diagram,

H = X, 

then

angle = ATN(H/(x+ray)

Hi Tom,

Unfortunately, i have only "X" and "ray".
I am searching for "H". Once i will know "H", i can get "ang" automatically.
Vice versa, if i know "ang", of course i get "H" easily.

It looks simple, but i must be tired. Thanks anyway.

[Anonymous]

the triangle 'ray, R and non-included angle (135 degrees)' is solvable

there's a solution here

http://www.teacherschoice.com.au/Maths_Library/Trigonometry/solve_trig_ASS.htm

have fun


bill

[Anonymous]

James wrote:
H <> X though. H is equal to the other side of that 45º triangle, less than X.

I don't think it's solvable with the information given. You have one side and no angles, which isn't much.

Hoping I'm wrong,

Hi James,

Thanks. Yes, H <> X. H is functiun of X (but function of ray too).
The centerpoint of the 45° angle is between ray and X. Hope this is understandable?

I am not sure it is solvable, but this could save me if it was. Why not to try?
Is there some mathematician around? Stuart James?

[TomWaltz]

Sorry, I misread the diagram. I did not see the little extension.

Bill is right.... that is a hard one, and will take a few equations!

[Anonymous]

bill wrote:
the triangle 'ray, R and non-included angle (135 degrees)' is solvable

there's a solution here

http://www.teacherschoice.com.au/Maths_Library/Trigonometry/solve_trig_ASS.htm

have fun


bill

Hi Bill,

Thanks for the link. I take a look. The time to make some translations, that's why i am so slow.

I have tried a solution with addition of angles, and at the end i got... an equality, something like A=A.
Bingo, May be i don't take the problem in the good way.

[Anonymous]

The answer is simple.

You cannot solve it. Why?

Look. You did draw an angle and now you want to measure it knowing only the radius.
To pursuade you. Draw that angle. You know the radius. You can change the angle but keep the radius. Is that right. So?? you cannot from X and r know what ang you have.


You simply cannot do that.

[Anonymous]

"You simply cannot do that"

two sides and one angle of the triangle are knowns

like i said, solvable

the solution, however, gave me a headache, even before i started to scroll thru it


bill